Nomor 1
A(10,4)
B(-2,-1)
AB² = (10+|-2|)² + (4+|-1|)²
AB² = 12² + 5²
AB² = 144+25
AB = 169
AB = √169
AB = 13 satuan
Nomor 2a
PR² = PQ² + QR²
PR² = 12² + 9²
PR² = 144 + 81
PR = 225
PR = 15 satuan
Nomor 2b
PK = MR = 8 satuan
RK² = PK² + PR²
RK² = 8² + 15²
RK² = 64 + 225
RK² = 289
RK = √289
RK = 17 satuan
Materi : Teorama Phytagoras
Soal Nomor 1
Titik A( x¹ = -2 dan y¹ = -1 )
Titik B( x² = 10 dan y² = 4 )
\___________________/
AB² = ( x² - x¹ )² + ( y² - y¹ )²
AB² = ( 10 + 2 )² + ( 4 + 1 )²
AB² = 12² + 5²
AB² = 144 + 25
AB² = 169
AB = √169
{ AB = 13 satuan }
Soal Nomor 2
Bagian A
Diagonal Bidang PR
PR² = PQ² + QR²
PR² = 12² + 9²
PR² = 144 + 81
PR² = 225
PR = √225
{ PR = 15 cm }
Bagian B
Diagonal Ruang RK
RK² = PQ² + QR² + MR²
RK² = 12² + 9² + 8²
RK² = 144 + 81 + 64
RK² = 225 + 64
RK² = 289
RK = √289
{ RK = 17 cm }
Semoga bisa membantu
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[answer.2.content]
